c^2=121c

Solution for c^2=121c equation:

c^2=121c

We move all terms to the left:

c^2-(121c)=0

a = 1; b = -121; c = 0;
Δ = b2-4ac
Δ = -1212-4·1·0
Δ = 14641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14641}=121$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-121)-121}{2*1}=\frac{0}{2}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-121)+121}{2*1}=\frac{242}{2}
=121
$